No, the value $9.8\frac {\mathrm {m}} {\mathrm {s}^2}$ is an approximation that is only valid at or near the Earth's surface. You can go a few miles up or down and it'll still be good enough, but once you …

The kgwt is not a unit which you should be using rather use the newton (N) as the unit of force. 9.8 crops up in a number of situations. The force of gravitational attraction on a mass of 1 kg on the Earth is …

Apr 9, 2019 · 9.8 m/s^2 is not 'the Earth's gravity', it's the at-mean-sea-level acceleration due to Earth's gravity. The acceleration would be quite different if measured elsewhere, like at the lunar orbit. The …

Feb 1, 2026 · Get your coupon Science Chemistry Chemistry questions and answers how do i do the 9.81 m/s2 of mg book mass. please help explain and answer

Science Physics Physics questions and answers 00% Part (b) (15 kg)• (9.81 m/s2) = ? 0 147 kg•m/s2 150 kg•m/s2 200 kg•m/s2 147.15 kg•m/s2 100 kg•m/s2 140 kg•m/s2 Submit Hint 4% deduction per …

1. The piston of a vertical piston-cylinder device containing a gas has a mass of 60 kg and a cross-sectional area of 0.04 m2, as shown in the figure. The local atmospheric pressure is 0.97 bar, and …

The gravitational acceleration is 9.81 m/s2 here on Earth at sea level. What is the gravitational acceleration on the top of Mount Everest? It is zero O It is slightly less than 9.81 m/s. It is 9.81 m/s, …

Common Values: Gravity (g) = 9.81 m/s2 = 32.2 ft/s2 Swater = 9.81 kN/m3 = 62.4 lb/ft3 water = 1000 kg/m² = 1.94 slugs/ft3 Yair = 1.23 kg/m3 = 2.38x10-3 slug/ft3 Atmospheric pressure at sea level = …

Question: Part (b) (15 kg)• (9.81 m/s2) = ? O 140 kg•m/s? O 147 kg•m/s2 O 147.15 kg•m/s2 O 150 kg•m/s2 O 100 kg•m/s? O 200 kg•m/s? (C) 15.6 cm - 2.6 mm = ? O 15 cm O 15.30 cm O 15.300 cm …

Engineering Mechanical Engineering Mechanical Engineering questions and answers g = 9.81 m/s2 , acceleration of gravity 𝜌 = 1000 Kg/m3 , water density 𝜇 = 10-3 Pa*s, dynamic viscosity of water …